1.4-Operations on Real Numbers

1.4-Operations on Real Numbers Important Formulae

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Grade 9 → Math → Number Systems → 1.4-Operations on Real Numbers

After successful completion of this topic, you should be able to:

  • Classify the numbers as rational or irrational.

Real numbers include rational and irrational numbers, and they can be subjected to various arithmetic operations: addition, subtraction, multiplication, and division. Understanding these operations is fundamental to working with real numbers in mathematics.

1. Addition of Real Numbers:

The addition of real numbers follows the associative and commutative properties. This means that for any real numbers $a$, $b$, and $c$:

  • Commutative Property: $a + b = b + a$
  • Associative Property: $(a + b) + c = a + (b + c)$

For example, if $a = 3$, $b = 5$, and $c = 7$:

  • $3 + 5 = 8$ and $5 + 3 = 8$ (commutative)
  • $(3 + 5) + 7 = 15$ and $3 + (5 + 7) = 15$ (associative)

2. Subtraction of Real Numbers:

Subtraction is not commutative or associative. For real numbers $a$ and $b$:

  • Commutative Property: $a - b \neq b - a$
  • Associative Property: $(a - b) - c \neq a - (b - c)$

For example, $5 - 3 = 2$, but $3 - 5 = -2$. Thus, the order of subtraction matters.

3. Multiplication of Real Numbers:

Multiplication of real numbers also follows the associative and commutative properties:

  • Commutative Property: $a \times b = b \times a$
  • Associative Property: $(a \times b) \times c = a \times (b \times c)$

Additionally, the distributive property holds for multiplication over addition:

  • Distributive Property: $a \times (b + c) = a \times b + a \times c$

For instance, for $a = 2$, $b = 3$, and $c = 4$:

  • $2 \times 3 = 6$ and $3 \times 2 = 6$ (commutative)
  • $(2 \times 3) \times 4 = 24$ and $2 \times (3 \times 4) = 24$ (associative)
  • $2 \times (3 + 4) = 14$ and $2 \times 3 + 2 \times 4 = 14$ (distributive)

4. Division of Real Numbers:

Division is neither commutative nor associative. For real numbers $a$ and $b$ (where $b \neq 0$):

  • Commutative Property: $a \div b \neq b \div a$
  • Associative Property: $(a \div b) \div c \neq a \div (b \div c)$

For example, $6 \div 2 = 3$, while $2 \div 6 \approx 0.33$. The order of division significantly affects the outcome.

5. Properties of Operations:

  • Closure Property: The sum or product of any two real numbers is a real number.
  • Identity Elements: The identity element for addition is $0$ (i.e., $a + 0 = a$), and for multiplication, it is $1$ (i.e., $a \times 1 = a$).
  • Inverse Elements: For addition, the inverse of $a$ is $-a$ (i.e., $a + (-a) = 0$); for multiplication, the inverse is $\frac{1}{a}$ (i.e., $a \times \frac{1}{a} = 1$, where $a \neq 0$).

Understanding these operations and their properties is essential for solving mathematical problems and for the application of real numbers in various contexts.


Master Uegly, Public domain, via Wikimedia Commons

Classify the following numbers as rational or irrational:

  1. 2 - $\sqrt{5}$
  2. (3 + $\sqrt{23}$) - $\sqrt{23}$
  3. $\dfrac{2\sqrt{7}}{7\sqrt{7}}$
  4. $\dfrac{1}{\sqrt{2}}$
  5. 2$\pi$

Solution:

Classifying Numbers as Rational or Irrational
Classifications are as follows:
  1. 2 - $\sqrt{5}$: Irrational
  2. (3 + $\sqrt{23}$) - $\sqrt{23}$: Rational
  3. $\dfrac{2\sqrt{7}}{7\sqrt{7}}$: Rational
  4. $\dfrac{1}{\sqrt{2}}$: Irrational
  5. 2$\pi$: Irrational

Simplify each of the following expressions:

  1. (3+ $\sqrt{3}$)(2+ $\sqrt{2}$)
  2. (3+ $\sqrt{3}$)(3- $\sqrt{3}$)
  3. ( $\sqrt{5}$ +$ \sqrt{2}$)$^2$
  4. ( $\sqrt{5}$ − $\sqrt{2}$)( $\sqrt{5}$ + $\sqrt{2}$)

Solution:

Simplifying Expressions
The simplified forms are:
  1. (3 + $\sqrt{3}$)(2 + $\sqrt{2}$) = $6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6}$
  2. (3 + $\sqrt{3}$)(3 - $\sqrt{3}$) = $9 - 3 = 6$
  3. ($\sqrt{5}$ + $\sqrt{2}$)$^2$ = $5 + 2 + 2\sqrt{10} = 7 + 2\sqrt{10}$
  4. ($\sqrt{5}$ − $\sqrt{2}$)($\sqrt{5}$ + $\sqrt{2}$) = $5 - 2 = 3$

Recall, $\pi$ is defined as the ratio of the circumference (say c) of a circle to its diameter (say d). That is, $\pi$ = $\dfrac{c}{d}$⋅ This seems to contradict the fact that $\pi$ is irrational. How will you resolve this contradiction?

Solution:
There is no contradiction. Remember that when you measure a length with a scale or any other device, you only get an approximate rational value. So, you may not realise that either c or d is irrational.

Represent $\sqrt{9.3}$ on the number line.

Solution:

Representing $\sqrt{9.3}$ on the Number Line

To represent $\sqrt{9.3}$ on the number line, first estimate its value. Since $9 < 9.3 < 10$, we have $3 < \sqrt{9.3} < \sqrt{10}$. Knowing $\sqrt{10} \approx 3.16$, we find that $3 < \sqrt{9.3} < 3.16$. Mark a point slightly to the right of 3 on the number line, approximately 3.05 to 3.1, to represent $\sqrt{9.3}$.

Rationalise the denominators of the following:

  1. $\dfrac{1}{\sqrt{7}}$
  2. $\dfrac{1}{\sqrt{7} - \sqrt{6}}$
  3. $\dfrac{1}{\sqrt{5} + \sqrt{2}}$
  4. $\dfrac{1}{\sqrt{7} + 2}$

Solution:

Rationalising Denominators
The rationalised forms are:
  1. $\dfrac{1}{\sqrt{7}} = \dfrac{\sqrt{7}}{7}$
  2. $\dfrac{1}{\sqrt{7} - \sqrt{6}} = \dfrac{\sqrt{7} + \sqrt{6}}{1} = \sqrt{7} + \sqrt{6}$
  3. $\dfrac{1}{\sqrt{5} + \sqrt{2}} = \dfrac{\sqrt{5} - \sqrt{2}}{3}$
  4. $\dfrac{1}{\sqrt{7} + 2} = \dfrac{\sqrt{7} - 2}{3}$