11.2-Surface Area of a Sphere

11.2-Surface Area of a Sphere Important Formulae

You are currently studying
Grade 9 → Math → Surface Area/Volume → 11.2-Surface Area of a Sphere

After successful completion of this topic, you should be able to:

  • To calculate surface area of a sphere.


A sphere is a perfectly symmetrical three-dimensional shape where every point on its surface is equidistant from its center. The distance from the center of the sphere to any point on its surface is called the radius (r).

The surface area of a sphere can be calculated using the following formula:

Surface Area (SA) = $4\pi r^2$

Where:

  • $SA$ = Surface Area of the sphere
  • $r$ = Radius of the sphere
Derivation of Surface Area Formula

To understand the derivation of the surface area formula, consider a sphere with radius $r$. Imagine wrapping the surface of the sphere with a thin layer of paint or wrapping it with a cloth. The total area covered would be the surface area of the sphere.

The formula can be derived by using the method of integration in calculus, but for Grade 9, we can approach it conceptually. Consider slicing the sphere into infinitely thin circular disks stacked on top of each other. The surface area can then be calculated by integrating the circumference of these circles.

The circumference of a circle at any point on the sphere is given by:

Circumference = $2\pi r$

As we stack these circles from the bottom to the top of the sphere, the height of each infinitesimal disk can be approximated. When integrating these circles, we would account for the radius at each point which changes depending on the height.

Properties of a Sphere
  • The radius is constant from the center to any point on the surface.
  • All diameters of a sphere are equal in length and measure $2r$.
  • The surface area increases with the square of the radius, meaning if the radius doubles, the surface area increases by a factor of four.
Example Calculation

Let’s calculate the surface area of a sphere with a radius of $5$ cm.

Using the formula:

SA = $4\pi r^2$

Substituting $r = 5$ cm:

SA = $4\pi (5)^2$

SA = $4\pi \times 25$

SA = $100\pi$

Thus, the surface area of the sphere is $100\pi$ cm². For practical calculations, using $ \pi \approx 3.14$, we can further approximate the surface area:

SA $\approx 100 \times 3.14 = 314$ cm².

Applications of Surface Area of a Sphere

The concept of surface area is crucial in various real-world applications:

  • In manufacturing spherical objects like balls and globes, ensuring adequate material use for covering.
  • In science, calculating the surface area of celestial bodies such as planets.
  • In biology, understanding the surface area of cells for nutrient absorption.

Understanding the surface area of a sphere is essential in solving real-life problems and applying mathematical concepts in various fields.


Geek3, CC BY 3.0, via Wikimedia Commons

Find the surface area of a sphere of radius:
(i) 10.5cm
(ii) 5.6cm
(iii) 14cm

Solution:
(i) 1386 cm$^2$
(ii) 394.24 cm$^2$
(iii) 2464 cm$^2$

Find the surface area of a sphere of diameter:
(i) 14 cm
(ii) 21 cm
(iii) 3.5 m

Solution:
(i) 616 cm$^2$
(ii) 1386 cm$^2$
(iii) 38.5 m$^2$

Find the total surface area of a hemisphere of radius 10 cm. (Use $\pi$ = 3.14)

Solution:
Total surface area of a hemisphere = 942 cm$^2$

The radius of a spherical balloon increases from 7 cm to 14 cm as air is being pumped into it. Find the ratio of surface areas of the balloon in the two cases.

Solution:
Ratio of surface areas = 1:4

A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs. 16 per 100 cm$^2$.

Solution:
Cost of tin-plating = Rs. 27.72

Find the radius of a sphere whose surface area is 154 cm$^2$.

Solution:
Radius of a sphere = 3.5 cm

The diameter of the moon is approximately one fourth of the diameter of the earth. Find the ratio of their surface areas.

Solution:
Ratio of their surface areas = 1:16

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

Solution:
Outer curved surface area of the bowl = 173.25 cm$^2$

A right circular cylinder just encloses a sphere of radius r (see Fig. 11.10). Find
(i) Surface area of the sphere,
(ii) Curved surface area of the cylinder,
(iii) Ratio of the areas obtained in (i) and (ii).

Solution:
(i) 4 $\pi$ r$^2$
(ii) 4 $\pi$ r$^2$
(iii) 1:1