4.3-Chance and Probability

4.3-Chance and Probability Important Formulae

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4.3 - Chance and Probability
  • Chance refers to the likelihood of an event occurring, ranging from 0 (impossible) to 1 (certain).
  • Probability is a measure of the chance of an event happening.
  • The probability of an event $P(E)$ is given by the formula: $P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$
  • For a fair coin toss, the probability of heads or tails is $P(\text{Head}) = \frac{1}{2}$
  • The sum of the probabilities of all possible outcomes in an experiment is always 1.
  • Sample space: The set of all possible outcomes of an experiment.

4.3 - Chance and Probability

In this section, we will learn about the concepts of chance and probability, which deal with the likelihood of an event occurring. These concepts are essential in understanding and analyzing various outcomes in everyday situations, such as tossing a coin or rolling a die.

What is Chance?

Chance refers to the likelihood or possibility of an event happening. It is often expressed as a ratio or a percentage. For example, if you toss a coin, the chance of getting heads or tails is 50%, or 1 out of 2. The higher the chance, the more likely the event will occur.

What is Probability?

Probability is a numerical value that represents the likelihood of an event. It is a measure of how likely an event is to occur and is always a number between 0 and 1, where 0 indicates that the event will not happen, and 1 means it is certain to happen. The probability of an event is calculated using the following formula:

Probability $P(E)$ of an event $E$ is given by:

$P(E) = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

Types of Events

Events can be classified into different types based on their nature:

  • Simple Event: An event that consists of a single outcome. For example, rolling a 3 on a die.
  • Compound Event: An event that consists of more than one outcome. For example, rolling an even number on a die.
  • Impossible Event: An event that cannot happen. For example, rolling a 7 on a standard die.
  • Certain Event: An event that is certain to happen. For example, drawing a card from a deck and getting a card that is either red or black.
Experimental Probability

Experimental probability is the probability of an event occurring based on experimental or observed data. It is calculated by performing an experiment and recording the outcomes. The formula for experimental probability is:

$P(E) = \dfrac{\text{Number of times event E occurred}}{\text{Total number of trials}}$

Example of Experimental Probability

If a die is rolled 100 times and the number 4 comes up 20 times, the experimental probability of rolling a 4 is:

$P(\text{4}) = \dfrac{20}{100} = 0.2$

Theoretical Probability

Theoretical probability, on the other hand, is based on reasoning or logic, and it is determined without conducting an actual experiment. It is based on the assumption that all outcomes are equally likely. For example, when rolling a fair six-sided die, the theoretical probability of rolling a number between 1 and 6 is:

$P(\text{any number from 1 to 6}) = \dfrac{1}{6}$

Probability of Multiple Events

When dealing with multiple events, we can calculate the probability of their occurrence using different methods:

  • Independent Events: If the occurrence of one event does not affect the occurrence of the other, the events are said to be independent. For example, tossing two coins. The probability of both coins landing heads is:
  • $P(\text{Heads on Coin 1 and Heads on Coin 2}) = P(\text{Heads on Coin 1}) \times P(\text{Heads on Coin 2}) = \dfrac{1}{2} \times \dfrac{1}{2} = \dfrac{1}{4}$

  • Dependent Events: If the occurrence of one event affects the occurrence of the other, the events are dependent. For example, drawing cards from a deck without replacement. The probability of drawing a red card and then a black card is:
  • $P(\text{Red then Black}) = P(\text{Red}) \times P(\text{Black after Red}) = \dfrac{26}{52} \times \dfrac{26}{51}$

Conclusion

Understanding the concepts of chance and probability helps us make better predictions and decisions based on the likelihood of events. It is widely used in various fields, such as gaming, sports, statistics, and even in daily life.

List the outcomes you can see in these experiments.

(a) Spinning a wheel
(b) Tossing two coins together

Solution:

Outcomes of Spinning a Wheel

The possible outcomes when spinning a wheel depend on the number and type of sections on the wheel. For example, if the wheel is divided into 4 equal parts labeled A, B, C, and D, the outcomes will be:

  • A
  • B
  • C
  • D
Outcomes of Tossing Two Coins Together

When tossing two coins, the possible outcomes are:

  • HH (Head on both coins)
  • HT (Head on the first coin, Tail on the second coin)
  • TH (Tail on the first coin, Head on the second coin)
  • TT (Tail on both coins)

When a die is thrown, list the outcomes of an event of getting:

(i) (a) a prime number
(b) not a prime number.

(ii) (a) a number greater than 5
(b) a number not greater than 5.

Solution:

When a die is thrown, list the outcomes of an event of getting:
(i) (a) a prime number
  • Prime numbers on a die: 2, 3, 5
(i) (b) not a prime number
  • Not a prime number: 1, 4, 6
(ii) (a) a number greater than 5
  • Numbers greater than 5: 6
(ii) (b) a number not greater than 5
  • Numbers not greater than 5: 1, 2, 3, 4, 5

Find the:

(a) Probability of the pointer stopping on D in (Question 1-(a))?
(b) Probability of getting an ace from a well shuffled deck of 52 playing cards?
(c) Probability of getting a red apple. (See figure below)

Solution:

Find the:


(a) Probability of the pointer stopping on D in (Question 1-(a))?
The probability of an event happening is given by the formula:
$P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$
If the pointer is equally likely to stop on any of the four sections A, B, C, or D, then:
$P(\text{D}) = \frac{1}{4}$

(b) Probability of getting an ace from a well shuffled deck of 52 playing cards?
In a deck of 52 cards, there are 4 aces (one for each suit: hearts, diamonds, clubs, and spades). The total number of outcomes is 52, and the number of favorable outcomes (getting an ace) is 4.
$P(\text{Ace}) = \frac{4}{52} = \frac{1}{13}$

(c) Probability of getting a red apple. (See figure below)
Assume there are 10 apples in total, 4 of which are red. The total number of outcomes is 10, and the number of favorable outcomes (getting a red apple) is 4.
$P(\text{Red Apple}) = \frac{4}{10} = \frac{2}{5}$

Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of:

(i) getting a number 6?
(ii) getting a number less than 6?
(iii) getting a number greater than 6?
(iv) getting a 1-digit number?

Solution:

Probability Questions

(i) Probability of getting a number 6:

The total number of slips is 10, and only one slip has the number 6. So, the probability is:

Probability = $ \frac{1}{10} $

(ii) Probability of getting a number less than 6:

The numbers less than 6 are 1, 2, 3, 4, and 5, so there are 5 favorable outcomes. The probability is:

Probability = $ \frac{5}{10} = \frac{1}{2} $

(iii) Probability of getting a number greater than 6:

The numbers greater than 6 are 7, 8, 9, and 10, so there are 4 favorable outcomes. The probability is:

Probability = $ \frac{4}{10} = \frac{2}{5} $

(iv) Probability of getting a 1-digit number:

All the numbers in the box (1 to 10) are 1-digit numbers. So, there are 10 favorable outcomes. The probability is:

Probability = $ \frac{10}{10} = 1 $

If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non blue sector?

Solution:

Question 1: What is the probability of getting a green sector?

There are 3 green sectors, 1 blue sector, and 1 red sector on the spinning wheel. The total number of sectors is:

$3 + 1 + 1 = 5$

The probability of getting a green sector is the ratio of the number of green sectors to the total number of sectors:

Probability of getting a green sector = $\frac{3}{5}$

Question 2: What is the probability of getting a non-blue sector?

The total number of sectors is 5, and there is 1 blue sector. The number of non-blue sectors is:

$3$ green sectors + $1$ red sector = $4$ non-blue sectors

The probability of getting a non-blue sector is the ratio of the number of non-blue sectors to the total number of sectors:

Probability of getting a non-blue sector = $\frac{4}{5}$

Find the probabilities of the events given in Question 2.

Solution:

Probability when a die is thrown
(i) Probability of a prime number

The numbers on a die are: $1, 2, 3, 4, 5, 6$.

The prime numbers between 1 and 6 are: $2, 3, 5$.

The total number of possible outcomes is 6.

The number of favorable outcomes for a prime number is 3 (since $2, 3, 5$ are prime).

So, the probability of getting a prime number is: $P(\text{prime number}) = \dfrac{3}{6} = \dfrac{1}{2}$.

(i) Probability of not a prime number

The numbers on a die are: $1, 2, 3, 4, 5, 6$.

The numbers that are not prime are: $1, 4, 6$.

The number of favorable outcomes for not a prime number is 3 (since $1, 4, 6$ are not prime).

So, the probability of not getting a prime number is: $P(\text{not prime number}) = \dfrac{3}{6} = \dfrac{1}{2}$.

(ii) Probability of a number greater than 5

The numbers on a die are: $1, 2, 3, 4, 5, 6$.

The numbers greater than 5 are: $6$.

The number of favorable outcomes for a number greater than 5 is 1 (since only $6$ is greater than 5).

So, the probability of getting a number greater than 5 is: $P(\text{greater than 5}) = \dfrac{1}{6}$.

(ii) Probability of a number not greater than 5

The numbers on a die are: $1, 2, 3, 4, 5, 6$.

The numbers that are not greater than 5 are: $1, 2, 3, 4, 5$.

The number of favorable outcomes for a number not greater than 5 is 5 (since $1, 2, 3, 4, 5$ are not greater than 5).

So, the probability of getting a number not greater than 5 is: $P(\text{not greater than 5}) = \dfrac{5}{6}$.