4.1-Linear Equations

4.1-Linear Equations Important Formulae

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Grade 9 → Math → Linear Equations → 4.1-Linear Equations

After successful completion of this topic, you should be able to:

  • Understand characteristics of a linear equation.

A linear equation is an equation of the form:

$ ax + b = 0 $, where $ a \neq 0 $.

In this equation:

  • $ x $ is the variable.
  • $ a $ is the coefficient of $ x $.
  • $ b $ is a constant term.

Linear equations can be solved using various methods. The solution to a linear equation is the value of $ x $ that makes the equation true.

Types of Linear Equations

Linear equations can be categorized into different types based on the number of variables:

  • Single Variable: An equation in one variable, e.g., $ 2x + 3 = 7 $.
  • Two Variables: An equation in two variables, e.g., $ 3x + 4y = 12 $.
Graphical Representation

A linear equation in two variables can be represented graphically as a straight line on a Cartesian plane. The general form is:

$ Ax + By + C = 0 $.

The slope-intercept form is:

$ y = mx + c $, where:

  • $ m $ is the slope of the line.
  • $ c $ is the y-intercept.
Methods to Solve Linear Equations

There are several methods to solve linear equations:

  • Graphical Method: Plotting the equations on a graph to find the point of intersection.
  • Substitution Method: Solving one equation for a variable and substituting into the other equation.
  • Elimination Method: Adding or subtracting equations to eliminate one variable.
Example of a Single Variable Linear Equation

Consider the equation:

$ 2x - 4 = 0 $.

To solve for $ x $:

  1. Add 4 to both sides: $ 2x = 4 $.
  2. Divide by 2: $ x = 2 $.
Example of a Two Variable Linear Equation

Consider the system of equations:

  • $ 2x + 3y = 6 $
  • $ x - y = 1 $

Using the substitution method:

  1. From the second equation, solve for $ x $: $ x = y + 1 $.
  2. Substitute into the first equation: $ 2(y + 1) + 3y = 6 $.
  3. Simplify: $ 2y + 2 + 3y = 6 $.
  4. Combine like terms: $ 5y + 2 = 6 $.
  5. Subtract 2 from both sides: $ 5y = 4 $.
  6. Divide by 5: $ y = \frac{4}{5} $.

Now substitute back to find $ x $:

  1. $ x = \frac{4}{5} + 1 = \frac{9}{5} $.
Applications of Linear Equations

Linear equations are widely used in various fields such as:

  • Business for profit and loss calculations.
  • Science for calculating relationships between variables.
  • Engineering for designing structures.

The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.

(Take the cost of a notebook to be Rs. x and that of a pen to be Rs. y).

Express the following linear equations in the form ax + by + c = 0 and indicate the 
values of a, b and c in each case:
(i)2x+3y = 9.35
(ii)x - $\dfrac{y}{5}$ - 10 =0
(iii) -2x+3y = 6
(iv) x = 3y

(v) 2x = - 5y
(vi) 3x+2 = 0
(vii) y - 2 = 0
(viii) 5 = 2x

Solution:

Linear Equations in Standard Form

(i) $2x + 3y - 9.35 = 0$; $a = 2$, $b = 3$, $c = -9.35$

(ii) $x - \dfrac{y}{5} - 10 = 0$; $a = 1$, $b = -\dfrac{1}{5}$, $c = -10$

(iii) $-2x + 3y - 6 = 0$; $a = -2$, $b = 3$, $c = -6$

(iv) $x - 3y = 0$; $a = 1$, $b = -3$, $c = 0$

(v) $2x + 5y = 0$; $a = 2$, $b = 5$, $c = 0$

(vi) $3x + 2 = 0$; $a = 3$, $b = 0$, $c = 2$

(vii) $y - 2 = 0$; $a = 0$, $b = 1$, $c = -2$

(viii) $2x - 5 = 0$; $a = 2$, $b = 0$, $c = -5$