11.3-Volume of a Right Circular Cone

11.3-Volume of a Right Circular Cone Important Formulae

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Grade 9 → Math → Surface Area/Volume → 11.3-Volume of a Right Circular Cone

After successful completion of this topic, you should be able to:

  • To calculate volume of a right circular cone.


A right circular cone is a three-dimensional geometric shape that has a circular base and a single vertex. The volume of a right circular cone can be calculated using a specific formula derived from the principles of geometry.

Definition of a Right Circular Cone

A right circular cone consists of:

  • A circular base with radius $r$
  • A height $h$ measured from the base to the apex (vertex) of the cone
  • A slant height $l$, which is the distance from the apex to any point on the circumference of the base
Volume Formula

The volume $V$ of a right circular cone can be expressed by the formula:

$V = \frac{1}{3} \pi r^2 h$

Where:

  • $V$ = Volume of the cone
  • $\pi$ = Pi, approximately equal to 3.14
  • $r$ = Radius of the base
  • $h$ = Height of the cone
Derivation of the Volume Formula

The volume of a cone can be derived by comparing it with a cylinder. Consider a right circular cylinder with the same radius $r$ and height $h$. The volume of the cylinder $V_{cylinder}$ is given by:

$V_{cylinder} = \pi r^2 h$

It is known that the volume of a cone is one-third that of the cylinder with the same base and height. Therefore, we have:

$V = \frac{1}{3} V_{cylinder} = \frac{1}{3} \pi r^2 h$

Calculation of Volume

To calculate the volume of a right circular cone, substitute the values of $r$ and $h$ into the volume formula. For example, if the radius $r = 3 \text{ cm}$ and the height $h = 4 \text{ cm}$, the calculation would be:

$V = \frac{1}{3} \pi (3)^2 (4)$

$= \frac{1}{3} \pi (9)(4) = \frac{36}{3} \pi = 12\pi \text{ cm}^3$

Thus, the volume of the cone is approximately $12 \times 3.14 = 37.68 \text{ cm}^3$.

Applications of Cone Volume

Understanding the volume of a cone is essential in various real-life applications, including:

  • Determining the capacity of containers that are cone-shaped (like ice cream cones)
  • Calculating the amount of material needed for construction projects
  • Understanding natural formations, such as volcanic cones
Practice Problems

1. Find the volume of a cone with a radius of 5 cm and a height of 10 cm.

2. A conical tent has a base radius of 2.5 m and a height of 3 m. Calculate the volume of the tent.

3. If the volume of a cone is 50 cm³ and the radius is 2 cm, find the height of the cone.

These problems can help reinforce the concept of calculating the volume of right circular cones.


Filo gèn', CC BY-SA 4.0, via Wikimedia Commons

Find the volume of the right circular cone with:
(i) radius 6 cm, height 7 cm
(ii) radius 3.5 cm, height 12 cm

Solution:
(i) 264 cm$^3$
(ii) 154 cm$^3$

Find the capacity in litres of a conical vessel with:
(i) Radius 7 cm, slant height 25 cm
(ii) Height 12 cm, slant height 13cm

Solution:
(i) 1.232 l
(ii) $\dfrac{11}{35}$ l

The height of a cone is 15 cm. If its volume is 1570 cm$^3$, find the radius of the base. (Use $\pi$ = 3.14)

Solution:
Radius of the base = 10 cm

If the volume of a right circular cone of height 9 cm is 48$\pi$ cm$^3$, find the diameter of its base.

A conical pit of top diameter 3.5 m is 12 m deep. What is its capacity in kilolitres?

Solution:
Capacity in kilolitres = 38.5 kl

The volume of a right circular cone is 9856 cm$^3$. If the diameter of the base is 28 cm, find
(i) Height of the cone
(ii) Slant height of the cone
(iii) Curved surface area of the cone

Solution:
(i) 48 cm
(ii) 50 cm
(iii) 2200 cm$^2$

A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained.

Solution:
Volume of the solid = 100 $\pi$ cm$^3$

If the triangle ABC in the Question 7 above is revolved about the side 5 cm, then find the volume of the solid so obtained. Find also the ratio of the volumes of the two solids obtained in Questions 7 and 8.

Solution:
Volume of the solid = 240 $\pi$ cm$^3$,
Ratio of the volumes = 5:12

A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.

Solution:
Volume = 86.625 m$^3$,
Area of the canvas = 99.825 m$^2$