11.1-Surface Area of a Right Circular Cone

11.1-Surface Area of a Right Circular Cone Important Formulae

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Grade 9 → Math → Surface Area/Volume → 11.1-Surface Area of a Right Circular Cone

After successful completion of this topic, you should be able to:

  • To calculate surface area of a right circular cone.


A right circular cone is a three-dimensional geometric figure with a circular base and a single vertex (the apex) not in the same plane as the base. Understanding the surface area of a cone is essential in various applications, including engineering, architecture, and design.

The surface area of a right circular cone consists of two parts: the area of the base and the lateral (curved) surface area.

1. Components of Surface Area

The formula for the total surface area (TSA) of a right circular cone is given by:

$ \text{TSA} = \pi r (r + l) $

where:

  • $ r $ = radius of the base of the cone
  • $ l $ = slant height of the cone
  • $ \pi $ = constant approximately equal to 3.14
2. Area of the Base

The base of the cone is a circle, and its area (A) can be calculated using the formula:

$ A = \pi r^2 $

3. Lateral Surface Area

The lateral surface area (LSA) of the cone is the area of the cone's curved surface. It can be calculated using the formula:

$ \text{LSA} = \pi r l $

4. Slant Height

The slant height ($ l $) of the cone can be found using the Pythagorean theorem if the height ($ h $) of the cone is known. The relationship is:

$ l = \sqrt{r^2 + h^2} $

Here:

  • $ h $ = height of the cone
  • $ r $ = radius of the base
5. Example Problem

To understand the application of the above formulas, consider a right circular cone with a radius of 3 cm and a height of 4 cm.

First, we calculate the slant height:

$ l = \sqrt{r^2 + h^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \, \text{cm} $

Next, we calculate the lateral surface area:

$ \text{LSA} = \pi r l = \pi \times 3 \times 5 = 15\pi \, \text{cm}^2 $

Then, we calculate the area of the base:

$ A = \pi r^2 = \pi \times 3^2 = 9\pi \, \text{cm}^2 $

Finally, we find the total surface area:

$ \text{TSA} = \pi r (r + l) = \pi \times 3 (3 + 5) = \pi \times 3 \times 8 = 24\pi \, \text{cm}^2 $

This example illustrates how to apply the formulas to calculate the surface area of a right circular cone effectively.


R. Sapiña, CC BY-SA 4.0, via Wikimedia Commons

Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area.

Solution:
Curved surface area = 165 cm$^2$

Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m.

Solution:
Total surface area of the cone= 1244.57 m$^2$

Curved surface area of a cone is 308 cm$^2$ and its slant height is 14 cm. Find
(i) Radius of the base and
(ii) Total surface area of the cone.

A conical tent is 10 m high and the radius of its base is 24 m. Find
(i) slant height of the tent.
(ii) cost of the canvas required to make the tent, if the cost of 1 m$^2$ canvas is Rs.70.

What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (Use $\pi$ = 3.14).

Solution:
Length of tarpaulin = 63 m

The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white-washing its curved surface at the rate of Rs. 210 per 100 m$^2$.

Solution:
Cost of white-washing = Rs. 1155

A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.

Solution:
Area of the sheet required = 5500 cm$^2$

A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is Rs. 12 per m$^2$, what will be the cost of painting all these cones? (Use $\pi$ = 3.14 and take $\sqrt{1.04}$ =1.02)

Solution:
Cost of painting = Rs. 384.34